document.write( "Question 856038: One integer is 10 less than 3 times another. The sum of their squares is 100. What are the two integers? \n" ); document.write( "
Algebra.Com's Answer #515702 by hamsanash1981@gmail.com(151)\"\" \"About 
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Let one of the integer be x then, another number = 3x-10
\n" ); document.write( "x^2 + (3x - 10)^2 = 100
\n" ); document.write( "x^2 + 9x^2 +100 - 60x = 100
\n" ); document.write( "10x^2 -60x = 0
\n" ); document.write( "10x^2 = 60 x
\n" ); document.write( "10 x = 60
\n" ); document.write( "x = 6\r
\n" ); document.write( "\n" ); document.write( "the other number is 3*6-10 => 8
\n" ); document.write( "The two integers are 6, 8
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