document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=856032>Question 856032</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given that x-1,2x+5,8x-1 are three consecutive terms of a GP. Find possible value of x and the common ratio of the progression </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #515700 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=515700\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> arithmetic <BR>\n" );
document.write( "x-1,2x+5,8x-1<BR>\n" );
document.write( "(2x+5)-(x-1)=(8x-1)-(2x+5)<BR>\n" );
document.write( "x = 12/5<BR>\n" );
document.write( "x-1 = 7/5, 2x+5 = 49/5, 8x-1 = 91/5<BR>\n" );
document.write( "d=42/5\r<BR>\n" );
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document.write( "geometric<BR>\n" );
document.write( "(2x+5)/(x-1)=(8x-1)/(2x+5)<BR>\n" );
document.write( "(2x+5)/(x-1)=a,b=(8x-1)/(2x+5)<BR>\n" );
document.write( "a = -2,   b = -2,   x = -3/4\r<BR>\n" );
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document.write( "ratio is -2 when x=-3/4\r<BR>\n" );
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document.write( "a = 3,   b = 3,   x = 8<BR>\n" );
document.write( "ratio is 3 when x=8 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );