document.write( "Question 9432: Hello.
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document.write( "Please help me on my homework. I couldn't find a resonable answer to this problem. The problem is: The sum of Paul and Beth Taulman's ages now is 67 years. Eight years ago Paul was twice as old as Beth. How old is each now?
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document.write( "Please reply as soon as possible. Thank you for your time.
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document.write( "Julia \n" );
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Algebra.Com's Answer #5157 by rapaljer(4671)![]() ![]() You can put this solution on YOUR website! Let P= Paul's age now \n" ); document.write( "B = Beth's age now \n" ); document.write( "P-8 = Paul's age 8 years ago \n" ); document.write( "B-8 = Beth's age 8 years ago\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "First equation, \n" ); document.write( "P+ B= 67, which means that B = 67 - P\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Second equation, \n" ); document.write( "P-8 = 2(B-8)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Substitute the B = 67 - P into the second equation: \n" ); document.write( "P - 8 = 2(B - 8) \n" ); document.write( "P - 8 = 2(67 - P - 8) \n" ); document.write( "P - 8 = 134 - 2P - 16 \n" ); document.write( "P - 8 = 118 - 2P\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Add + 2P to each side: \n" ); document.write( "P + 2P - 8 = 118 - 2P + 2P \n" ); document.write( "3P - 8 = 118 \n" ); document.write( "3P = 126 \n" ); document.write( "P = 42 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "B= 67 - P \n" ); document.write( "B = 67 - 42 \n" ); document.write( "B = 25\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check: Eight years ago, Paul was 34 and Beth was 17, and Paul was twice as old as Beth.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "R^2 at SCC \n" ); document.write( " \n" ); document.write( " |