document.write( "Question 72139This question is from textbook Algebra and Trigonometry: Structure and Method
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document.write( ": When Ace Airlines changed to planes that flew 100 km/h faster than its old ones, the time of its 2800 km Dallas-Seattle flight was reduced by 30 min. Find the speed of the new plane. \n" );
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Algebra.Com's Answer #51569 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! 2800/(X+100)+.5=2800/X \n" ); document.write( "(2800+.5X+50)/(X+100)=2800/X \n" ); document.write( "(2850+.5X)/(X+100)=2800/X NOW CROSS MULTIPLY \n" ); document.write( "(X+100)2800=X(2850+.5X) \n" ); document.write( "2800X+280000=2850X+.5X^2 \n" ); document.write( ".5X^2+50X-280000=0 \n" ); document.write( "X^2+100X-560000=0 \n" ); document.write( "(X-700)(X+800)=0 \n" ); document.write( "X-700=0 \n" ); document.write( "X=700 ANSWER FOR THE SPEED OF THE SLOWER AIRPLANE \n" ); document.write( "X+100=800 IS THE SPEED OF THE FASTER PLANE. \n" ); document.write( "PROOF \n" ); document.write( "2800/800+.5=2800/700 \n" ); document.write( "3.5+.5=4 \n" ); document.write( "4=4 \n" ); document.write( " \n" ); document.write( " |