document.write( "Question 72139This question is from textbook Algebra and Trigonometry: Structure and Method
\n" ); document.write( ": When Ace Airlines changed to planes that flew 100 km/h faster than its old ones, the time of its 2800 km Dallas-Seattle flight was reduced by 30 min. Find the speed of the new plane. \n" ); document.write( "
Algebra.Com's Answer #51569 by checkley75(3666)\"\" \"About 
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2800/(X+100)+.5=2800/X
\n" ); document.write( "(2800+.5X+50)/(X+100)=2800/X
\n" ); document.write( "(2850+.5X)/(X+100)=2800/X NOW CROSS MULTIPLY
\n" ); document.write( "(X+100)2800=X(2850+.5X)
\n" ); document.write( "2800X+280000=2850X+.5X^2
\n" ); document.write( ".5X^2+50X-280000=0
\n" ); document.write( "X^2+100X-560000=0
\n" ); document.write( "(X-700)(X+800)=0
\n" ); document.write( "X-700=0
\n" ); document.write( "X=700 ANSWER FOR THE SPEED OF THE SLOWER AIRPLANE
\n" ); document.write( "X+100=800 IS THE SPEED OF THE FASTER PLANE.
\n" ); document.write( "PROOF
\n" ); document.write( "2800/800+.5=2800/700
\n" ); document.write( "3.5+.5=4
\n" ); document.write( "4=4
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