document.write( "Question 856009: Find the equation of the line tangent to a circle x2 + y2 = 13 at (3,-2). \n" ); document.write( "
Algebra.Com's Answer #515682 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
First, look for the line containing points (0,0) and (3,-2). Assuming point (3,-2 )is also on the circle, find the line perpendicular to the just found line and containing the point (3,-2).\r
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\n" ); document.write( "\n" ); document.write( "Something worth checking: Is (3,-2) on the circle \"x%5E2%2By%5E2=13\"?
\n" ); document.write( "\"3%2A3%2B%28-2%29%5E2=13\"
\n" ); document.write( "\"9%2B4=13\", YES.\r
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\n" ); document.write( "\n" ); document.write( "Line (0,0) to (3,-2) is \"y=-%282%2F3%29x\";
\n" ); document.write( "A line perpendicular is \"y=%283%2F2%29x%2Bb\". THIS line must contain(3,-2).
\n" ); document.write( "\"b=y-%283%2F2%29x\"
\n" ); document.write( "\"b=-2-%283%2F2%29%2A3\"
\n" ); document.write( "\"b=-2-9%2F2\"
\n" ); document.write( "\"b=-4%2F2-9%2F2\"
\n" ); document.write( "\"b=-13%2F2\"
\n" ); document.write( "Line tangent to circle at (3,-2) is \"highlight%28y=%283%2F2%29x-13%2F2%29\".\r
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\n" ); document.write( "\n" ); document.write( "\"graph%28300%2C300%2C-6%2C6%2C-6%2C6%2C-sqrt%2813-x%5E2%29%2C%283%2F2%29x-13%2F2%29\"
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