document.write( "Question 72133This question is from textbook Advanced Algebra
\n" ); document.write( ": Write 5/(6-2i) in a+bi form. \n" ); document.write( "
Algebra.Com's Answer #51568 by bucky(2189)\"\" \"About 
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\"5%2F%286-2i%29\"
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\n" ); document.write( "to get this to the form a + bi begin by multiplying the given term by:
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\n" ); document.write( "\"%286+%2B+2i%29%2F%286%2B2i%29\"
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\n" ); document.write( "Note that this is equivalent to multiplying the given term by 1 because \"%286+%2B+2i%29%2F%286%2B2i%29\"
\n" ); document.write( "equals 1.
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\n" ); document.write( "The numerator multiplication of the 5 times the (6 + 2i) results in 30 + 20i.
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\n" ); document.write( "Then the denominator multiplication of \"%286+-+2i%29%2A%286+%2B+2i%29\" results in:
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\n" ); document.write( "\"+36+-+12i+%2B+12i+-4%2Ai%5E2\"
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\n" ); document.write( "The -12i and + 12i cancel each other out. Then recall that \"i%5E2\" by definition is -1.
\n" ); document.write( "Substituting -1 for \"i%5E2\" leads to:
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\n" ); document.write( "\"36+-4%2A%28-1%29+=+36+%2B+4+=+40\"
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\n" ); document.write( "This is the denominator ... +40. From above the numerator is 30 + 20i. So the answer is:
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\n" ); document.write( "\"%2830%2B20%2Ai%29%2F40+=+%283%2F4%29+%2B+%281%2F2%29%2Ai\"
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\n" ); document.write( "The answer to your problem is \"%283%2F4%29+%2B+%281%2F2%29%2Ai\" where \"a+=+%283%2F4%29\" and \"b=+%281%2F2%29\"
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\n" ); document.write( "Hope this helps you to understand complex numbers. Notice how you can eliminate complex
\n" ); document.write( "numbers in the denominator by multiplying the denominator by the same complex number with
\n" ); document.write( "a change in signs between the real and imaginary parts. This converts the denominator
\n" ); document.write( "to a real number.
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