document.write( "Question 72133This question is from textbook Advanced Algebra
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document.write( ": Write 5/(6-2i) in a+bi form. \n" );
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Algebra.Com's Answer #51568 by bucky(2189) ![]() You can put this solution on YOUR website! \n" ); document.write( ". \n" ); document.write( "to get this to the form a + bi begin by multiplying the given term by: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Note that this is equivalent to multiplying the given term by 1 because \n" ); document.write( "equals 1. \n" ); document.write( ". \n" ); document.write( "The numerator multiplication of the 5 times the (6 + 2i) results in 30 + 20i. \n" ); document.write( ". \n" ); document.write( "Then the denominator multiplication of \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "The -12i and + 12i cancel each other out. Then recall that \n" ); document.write( "Substituting -1 for \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "This is the denominator ... +40. From above the numerator is 30 + 20i. So the answer is: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "The answer to your problem is \n" ); document.write( ". \n" ); document.write( "Hope this helps you to understand complex numbers. Notice how you can eliminate complex \n" ); document.write( "numbers in the denominator by multiplying the denominator by the same complex number with \n" ); document.write( "a change in signs between the real and imaginary parts. This converts the denominator \n" ); document.write( "to a real number. \n" ); document.write( ".\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |