document.write( "Question 72133This question is from textbook Advanced Algebra
\n" ); document.write( ": Write 5/(6-2i) in a+bi form. \n" ); document.write( "

Algebra.Com's Answer #51567 by jim_thompson5910(35256) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"5%2F%286-2i%29\"$
\n" ); document.write( " $\"%285%2F%286-2i%29%29%28%286%2B2i%29%2F%286%2B2i%29%29\"$ Multiply both top and bottom by the complex conjugate of 6-2i
\n" ); document.write( " $\"%285%2A%286%2B2i%29%29%2F%2836%2B12i-12i-4%28-1%29%29\"$ FOIL the denominator (remember $\"i%5E2=-1\"$ )
\n" ); document.write( " $\"%285%2A%286%2B2i%29%29%2F%2836%2Bcross%2812i-12i%29-4%28-1%29%29\"$ The i terms cancel in the denominator
\n" ); document.write( " $\"%285%2A%286%2B2i%29%29%2F%2840%29%29\"$ Distribute the 5 among the parenthesis
\n" ); document.write( " $\"%2830%2B10i%29%2F%2840%29%29\"$
\n" ); document.write( " $\"30%2F40%2B%2810%2F40%29i\"$
\n" ); document.write( " $\"3%2F4%2B%281%2F4%29i\"$ Here's the answer in a+bi form where a=3/4 and b=1/4
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