document.write( "Question 855774: If a painting is 480 sq inches and the width of painting is 1 and one fifth its width, how do I fine dimensions of painting?
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Algebra.Com's Answer #515667 by ankor@dixie-net.com(22740)\"\" \"About 
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If a painting is 480 sq inches and the length of painting is 1 and one fifth its width,
\n" ); document.write( " how do I fine dimensions of painting?
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\n" ); document.write( "L * W = 480 sq/in
\n" ); document.write( "The length is 1 1/5 the width therefore:
\n" ); document.write( "L = 1.2W
\n" ); document.write( "Replace L with 1.2W in the area equation
\n" ); document.write( "1.2W * W = 480
\n" ); document.write( "1.2W^2 = 480
\n" ); document.write( "divide both sides by 1.2
\n" ); document.write( "W^2 = 480/1.2
\n" ); document.write( "W^2 = 400
\n" ); document.write( "W = \"sqrt%28400%29\"
\n" ); document.write( "W = 20\" is the width
\n" ); document.write( "I'll let you find the Length, check to see if L * W = 480
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