document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=72159>Question 72159</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Equation 1:   -A + 4B + C = 0      Equation 2: 3A - 2B + C = 0<BR>\n" );
document.write( "How do I answer the equations in terms of C? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #51563 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=51563\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -A+4B+C=0 ADD A & SUBTRACT 4B FROM BOTH SIDES.<BR>\n" );
document.write( "-A+A+4B-4B+C=A-4B NOW COMBINE LIKE TERMS. THUS:<BR>\n" );
document.write( "C=A-4B<BR>\n" );
document.write( "----------------------------------------------------------<BR>\n" );
document.write( "3A-2B+C=0 SUBTRACT 3A & ADD 2B TO BOTH SIDES.<BR>\n" );
document.write( "C=-3A+2B<BR>\n" );
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document.write( "I'm assuming the problem is to find the line equation through these 2 po=<BR>\n" );
document.write( "ints??????<BR>\n" );
document.write( "If that is so I don't know what they are doing with the ax+bx+c=3D0  for=<BR>\n" );
document.write( "mula.<BR>\n" );
document.write( "A line through these points (-1,4)(3,-2) has a slope<BR>\n" );
document.write( "(y2-y1)/(x2-x1)=3D (-2-4)/(3+1)=3D-6/4=3D-1.5 this is the slope.<BR>\n" );
document.write( "Now substitute either set of (x,y) points in the line formula & solve fo=<BR>\n" );
document.write( "r the y intercept (b).<BR>\n" );
document.write( "4=3D-1*-1.5+b<BR>\n" );
document.write( "4=3D1.5+b<BR>\n" );
document.write( "b=3D4-1.5<BR>\n" );
document.write( "b=3D2.5<BR>\n" );
document.write( "now we have the line equation of<BR>\n" );
document.write( "y=3D-1.5x+2.5<BR>\n" );
document.write( "Now I am lost as to what is asked for when they say a=3D-3/5c & b=3D-2/5=<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Sorry if this is not what you are looking for.\r<BR>\n" );
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document.write( "checkley75.<BR>\n" );
document.write( " </SPAN>\n" );
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