document.write( "Question 855917: 2 isosceles triangles have legs that are 26 and areas that are equal. If the base of one triangle is 48. Find the base of the other triangle ?
\n" ); document.write( "*i know that in an isosceles triangle the sides that are connected to the vertex angle is congruent and the base angles are also congruent* i have tried using the Pythagorean theorem but its not working*(Pythagorean theorem= a^2+b^2=C^2\r
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Algebra.Com's Answer #515628 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

 
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document.write( "Hi,
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document.write( "Perhaps this picture will help: 
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document.write( "the 'h' is a 'leg', other leg = 24 (h bisects the base)
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document.write( "hypotenuse = 26
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document.write( "line segment of Height to the base bisects the base (base = 48)
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document.write( "Therefore: 26^2 - 24^2 = h^2 = 100, h = 10
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document.write( " A =  = 240
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document.write( " Find the base of the other triangle 
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document.write( " A = 240 = 
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document.write( "    480= 
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document.write( "    480^2/b^2 = 26^2 - (b^2/4
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document.write( "    b^4  -4(26^2)b^2 + 4(480^2)  Let x = b^2
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document.write( "    x^2 - 2704x + - 921600
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document.write( "x = 400 0r x = 2304
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document.write( " b = 20  0r b = 48
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document.write( "the base of the other triangle is 20
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document.write( "CHECKING our answer***
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document.write( " 26^2 -10^2 = 576= h^2,   h = 24   AND  
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document.write( "Wish You the Best in your Studies.
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