document.write( "Question 855836: Solve using the substitution method.\r
\n" ); document.write( "\n" ); document.write( "4y+2x=40
\n" ); document.write( "3y-x=5\r
\n" ); document.write( "\n" ); document.write( "Post steps please.
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Algebra.Com's Answer #515585 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
\n" ); document.write( "Hi,
\n" ); document.write( "3y-x=5 ⇒ x = \"green%283y-5%29\"
\n" ); document.write( "4y+2x=40
\n" ); document.write( "4y+2(\"green%283y-5%29\")=40
\n" ); document.write( "4y + 6y - 10 = 40
\n" ); document.write( " 10y = 50
\n" ); document.write( " y = 5
\n" ); document.write( " x = \"green%283y-5%29+=+10\"
\n" ); document.write( "CHECKING our answer***
\n" ); document.write( "Using 3y-x = 5
\n" ); document.write( " 15-10 = 5
\n" ); document.write( "Wish You the Best in your Studies.\r
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