document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=72150>Question 72150</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Graph a line that passes through (4, -2) and is perpendicular to a line whose slope is -3. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #51557 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=51557\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a line that is perpendicular to a line with a slope of -3 has a slope of 1/3<BR>\n" );
document.write( "(the negative reciprical of the other slope.<BR>\n" );
document.write( "thus the equation of this line through (4,-2) is:<BR>\n" );
document.write( "-2=4/3+b<BR>\n" );
document.write( "b=-2-4/3<BR>\n" );
document.write( "b=-10/3<BR>\n" );
document.write( "thus the equation is<BR>\n" );
document.write( "y=x/3-10/3<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+y+=+x%2F3+-10%2F3%29+ ALIGN=MIDDLE  ALT=\"+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+y+=+x%2F3+-10%2F3%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, <BR>\n" );
document.write( "y = x/3 -10/3). <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );