document.write( "Question 855786: I am having difficulty with this question and was wondering if you could give me a hand
\n" ); document.write( "Five numbers have a median of 7, a mode of 9, a range of 5 and a mean of 7 what are the 5 numbers?
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Algebra.Com's Answer #515563 by KMST(5328) $\"\"$ $\"About$

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Mode is the most repeated value, so two of the numbers must be
\n" ); document.write( " $\"highlight%289%29\"$ and $\"highlight%289%29\"$ .
\n" ); document.write( "The median is a value such that as many of the numbers are lesser than the median as are greater than the median.
\n" ); document.write( "With five numbers, because 5 is odd, the median has to be one of the numbers,
\n" ); document.write( "so $\"highlight%287%29\"$ is one of the numbers,
\n" ); document.write( "and since two of the numbers are $\"9%3E7\"$ the other two numbers must be less than $\"7\"$ .
\n" ); document.write( "The range is the difference between the greatest and the least of the numbers.
\n" ); document.write( "The range is $\"5\"$ the greatest of the numbers is $\"9\"$ ,
\n" ); document.write( "so the least of the numbers is $\"9-5=highlight%284%29\"$ .
\n" ); document.write( "Knowing for of the numbers, and the mean $\"%287%29\"$ of the five numbers,
\n" ); document.write( "the fifth number, which I will call $\"x\"$ , can be found from the definition of mean:
\n" ); document.write( " $\"%284%2B7%2B9%2B9%2Bx%29%2F5=7\"$
\n" ); document.write( " $\"%2829%2Bx%29%2F5=7\"$
\n" ); document.write( " $\"29%2Bx=7%2A5\"$
\n" ); document.write( " $\"29%2Bx=35\"$
\n" ); document.write( " $\"x=35-29\"$
\n" ); document.write( " $\"x=highlight%286%29\"$ .
\n" ); document.write( "The five numbers are:
\n" ); document.write( " $\"highlight%284%29\"$ , $\"highlight%286%29\"$ , $\"highlight%287%29\"$ , $\"highlight%289%29\"$ and $\"highlight%289%29\"$ . \n" ); document.write( "

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