document.write( "Question 855779: Sketch a graph of the solution of the system of linear inequalities.
\n" ); document.write( "y≥1/2x+1/2
\n" ); document.write( "y≤4x−1/2
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Algebra.Com's Answer #515557 by brysca(112)\"\" \"About 
You can put this solution on YOUR website!
When graphed, both linear inequalities should look like this: \r
\n" ); document.write( "\n" ); document.write( "\"+graph%28+300%2C+200%2C+-4%2C+10%2C+-4%2C+10%2C+%28.5%2Ax%29%2B.5%2C+4x-.5%29+\"\r
\n" ); document.write( "\n" ); document.write( "To graph both inequalities manually, follow the expression y=mx+b where m is the slope (rise/run), and b is the y intercept.\r
\n" ); document.write( "\n" ); document.write( "To determine the solution set between the two graphs, we must put a test point.
\n" ); document.write( "We will use point (0,0) for this example\r
\n" ); document.write( "\n" ); document.write( "Red graph:
\n" ); document.write( "y ≥ .5x+.5
\n" ); document.write( "0 ≥ .5(0)+.5
\n" ); document.write( "0 ≥ .5
\n" ); document.write( "Is zero greater than .5? Of course not, so shade the upper side of the red graph\r
\n" ); document.write( "\n" ); document.write( "Green graph:
\n" ); document.write( "y ≤4x−.5
\n" ); document.write( "0 ≤ 4(0)-.5
\n" ); document.write( "0 ≤ -.5
\n" ); document.write( "Is zero less than -.5? No. So shade the right side of the green graph.
\n" ); document.write( "Now, knowing the solution set for green graph and the red graph, just shade in the sides they have in common.
\n" ); document.write( "In this problem, the shaded area should be in the middle of both of the graphs.
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