document.write( "Question 855763: I have the following question that I don't really get how to do. It is as follows:
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document.write( "\"Solve the following inequality problems. You must give your answer using the
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document.write( "interval notation. You must also give you answer in graphical form (using the
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document.write( "number line).
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document.write( "(a) 7 - 5x < -3 or 2x - 1 ≤ x - 2.
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document.write( "(b) 2 - 3x < 8 and 4x - 2 ≤ 3x + 1.
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document.write( "Can someone please answer the question so that I can understand how it's done?
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document.write( "Thank you in advance :)
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document.write( "zeedee \n" );
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Algebra.Com's Answer #515551 by rothauserc(4718) You can put this solution on YOUR website! (a) 7 - 5x < -3 or 2x - 1 ≤ x - 2 \n" ); document.write( "7 - 5x < -3 \n" ); document.write( "-5x < -10 \n" ); document.write( "when multiplying or dividing by a negative reverse the < or > \n" ); document.write( "x > 10 \n" ); document.write( "2x - 1 ≤ x - 2 \n" ); document.write( "x ≤ -1 \n" ); document.write( "so x is ≤ -1 or > 10 \n" ); document.write( "there are two intervals to mark on the number line \n" ); document.write( "(negative infinity, -1] this is closed on the right because -1 is included \n" ); document.write( "(10, infinity) \n" ); document.write( "(b) 2 - 3x < 8 and 4x - 2 ≤ 3x + 1 \n" ); document.write( "2 - 3x < 8 \n" ); document.write( "-3x < 6 \n" ); document.write( "x > -6 \n" ); document.write( "4x - 2 ≤ 3x + 1 \n" ); document.write( "x ≤ 3 \n" ); document.write( "so x > -6 and ≤ 3 \n" ); document.write( "we have one interval which is closed on the right \n" ); document.write( "(-6, 3] \n" ); document.write( " \n" ); document.write( " |