document.write( "Question 855700: larry invested part of his 29000 advance at 4% annual simple interest and the rest at 5 % annual simple interest. If his total yearly income from both accounts was 1180 find the amount invested at each rate? 4% and5% \n" ); document.write( "
Algebra.Com's Answer #515550 by mananth(16946)\"\" \"About 
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Part I 4.00% per annum ---x
\n" ); document.write( "Part II 5.00% per annum ---y
\n" ); document.write( "Total investment
\n" ); document.write( "x + 1 y= 29000 -------------1
\n" ); document.write( "Interest on both investments
\n" ); document.write( "4.00% x + 5.00% y= 1180
\n" ); document.write( "Multiply by 100
\n" ); document.write( "4 x + 5 y= 118000.00 --------2
\n" ); document.write( "Multiply (1) by -4
\n" ); document.write( "we get
\n" ); document.write( "-4 x -4 y= -116000.00
\n" ); document.write( "Add this to (2)
\n" ); document.write( "0 x 1 y= 2000
\n" ); document.write( "divide by 1
\n" ); document.write( " y = 2000
\n" ); document.write( "Part I 4.00% $ 27000
\n" ); document.write( "Part II 5.00% $ 2000
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\n" ); document.write( "CHECK
\n" ); document.write( "27000 --------- 4.00% ------- 1080.00
\n" ); document.write( "2000 ------------- 5.00% ------- 100.00
\n" ); document.write( "Total -------------------- 1180.00
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\n" ); document.write( "m.ananth@hotmail.ca
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