document.write( "Question 855701: How much of an alloy that is 30% copper should be mixed with 200 ounces of an alloy that is 70 % copper in order to get an alloy that is 50 % copper\r
\n" ); document.write( "\n" ); document.write( "this is what I came up with...is this right\r
\n" ); document.write( "\n" ); document.write( "x(30%)+(200)(70%)=200+x(50)
\n" ); document.write( ".3x+140=100+.5x
\n" ); document.write( "40=.2x
\n" ); document.write( "x=200
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Algebra.Com's Answer #515531 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
x how much to add or use\r
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\n" ); document.write( "\n" ); document.write( "\"%2830x%2B200%2A70%29%2F%28x%2B200%29=50\"\r
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\n" ); document.write( "\n" ); document.write( "Your initial setup seems good. Maybe you let the switch to decimal fractions confuse you?\r
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\n" ); document.write( "\n" ); document.write( "\"30x%2B200%2A70=50%28x%2B200%29\"
\n" ); document.write( "\"3x%2B200%2A7=5%28x%2B200%29\"\r
\n" ); document.write( "\n" ); document.write( "\"3x%2B1400=5x%2B1000\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28x=200%29\", and in fact this works as correct when tried as a check in our original equation.\r
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\n" ); document.write( "\n" ); document.write( "(Seemed strange to me also, ...until examining the AVERAGE of 30 and 70. Their middle value IS 50.)
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