document.write( "Question 855701: How much of an alloy that is 30% copper should be mixed with 200 ounces of an alloy that is 70 % copper in order to get an alloy that is 50 % copper\r
\n" );
document.write( "\n" );
document.write( "this is what I came up with...is this right\r
\n" );
document.write( "\n" );
document.write( "x(30%)+(200)(70%)=200+x(50)
\n" );
document.write( ".3x+140=100+.5x
\n" );
document.write( "40=.2x
\n" );
document.write( "x=200 \n" );
document.write( "
Algebra.Com's Answer #515531 by josgarithmetic(39618)![]() ![]() ![]() You can put this solution on YOUR website! x how much to add or use\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Your initial setup seems good. Maybe you let the switch to decimal fractions confuse you?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(Seemed strange to me also, ...until examining the AVERAGE of 30 and 70. Their middle value IS 50.) \n" ); document.write( " |