document.write( "Question 855670: Evaluate the expression when x = 6 and y = -2\r
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\n" ); document.write( "\n" ); document.write( "(y^3+√(x-2))/|4x-y|
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Algebra.Com's Answer #515522 by jim_thompson5910(35256)\"\" \"About 
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Evaluate the expression when x = 6 and y = -2\r
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\n" ); document.write( "\n" ); document.write( "(y^3+sqrt(x-2))/|4x-y| \r
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\n" ); document.write( "\n" ); document.write( "((-2)^3+sqrt(6-2))/|4(6)-(-2)| ... replace all copies of x with 6 and all copies of y with -2\r
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\n" ); document.write( "\n" ); document.write( "(-8+sqrt(6-2))/|4(6)-(-2)| \r
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\n" ); document.write( "\n" ); document.write( "(-8+sqrt(6-2))/|24 + 2| \r
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\n" ); document.write( "\n" ); document.write( "(-8+sqrt(4))/|26| \r
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\n" ); document.write( "\n" ); document.write( "(-8+sqrt(4))/26\r
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\n" ); document.write( "\n" ); document.write( "(-8+2)/26\r
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\n" ); document.write( "\n" ); document.write( "(-6)/26\r
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\n" ); document.write( "\n" ); document.write( "-3/13\r
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\n" ); document.write( "\n" ); document.write( "So, (y^3+sqrt(x-2))/|4x-y| = -3/13 when x = 6 and y = -2\r
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