document.write( "Question 855659: The length of a rectangle is 3 feet less than twice the width of the rectangle. If the perimeter of the rectangle is 444 feet, find the width and the length. \n" ); document.write( "
Algebra.Com's Answer #515512 by ramkikk66(644)\"\" \"About 
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document.write( "The length of a rectangle is 3 feet less than twice the width of the rectangle. If the perimeter of the rectangle is 444 feet, find the width and the length.\r\n" );
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document.write( "Let the width of rectangle be x\r\n" );
document.write( "Length = 2*x - 3\r\n" );
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document.write( "Perimeter = 2*(Length + Width) = 2*(2*x - 3 + x) = 2*(3*x - 3)\r\n" );
document.write( "= 6*x - 6 = 444 (given)\r\n" );
document.write( "\"6%2Ax+=+450\"\r\n" );
document.write( "\"x+=+75\"\r\n" );
document.write( "Length = 2*75 - 3 = 147\r\n" );
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document.write( "Width is \"highlight%2875%29\" ft and length is \"highlight%28147%29\" ft.\r\n" );
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document.write( "Hope you got it :)\r\n" );
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