document.write( "Question 855637: The one-to-one functions g and h are defined as follows. \r
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\n" ); document.write( "\n" ); document.write( "g^-1(4)=\r
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\n" ); document.write( "\n" ); document.write( "h^-1(x)=\r
\n" ); document.write( "\n" ); document.write( "(h^-1 o h)(7)=
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Algebra.Com's Answer #515484 by Edwin McCravy(20055)\"\" \"About 
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document.write( "The one-to-one functions g and h are defined as follows. \r\n" );
document.write( " g={(-7,-6), (-5,4), (4,-7)(7,6)}\r\n" );
document.write( " h(x)= 3x-14 \r\n" );
document.write( " Find the following. \r\n" );
document.write( " g-1(4)=\r\n" );
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document.write( "\"g-1(4)\" just says \"Find the pair of coordinates that has 4 for its\r\n" );
document.write( " y-coordinate, and the answer is its x-coordinate\".  So we look through those\r\n" );
document.write( " and find (-5,4) is the only one of those up there that has a 4 for it's y-\r\n" );
document.write( "coordinate, and so its x-coordinate is -5 and we write:\r\n" );
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document.write( "g-1(4)=-5   \r\n" );
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document.write( "-------------------------------------------------------------- \r\n" );
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document.write( "h-1(x)= \r\n" );
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document.write( "Start with\r\n" );
document.write( "    h(x) = 3x-14\r\n" );
document.write( "Change \"h(x): to \"y\"\r\n" );
document.write( "       y = 3x-14\r\n" );
document.write( "Interchange x and y:\r\n" );
document.write( "       x = 3y-14\r\n" );
document.write( "Solve for y:\r\n" );
document.write( "    x+14 = 3y\r\n" );
document.write( "(x+14)/3 = y  \r\n" );
document.write( "Change y to h^-1(x)\r\n" );
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document.write( "h-1(x) = (x+14)/3 \r\n" );
document.write( "-------------------------\r\n" );
document.write( " (h-1 o h)(7)=\r\n" );
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document.write( "That's the same as:\r\n" );
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document.write( "h-1(h(7)) = ?\r\n" );
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document.write( "First find h(7)\r\n" );
document.write( "   h(x) = 3x-14\r\n" );
document.write( "   h(7) = 3(7)-14\r\n" );
document.write( "   h(7) = 21-14\r\n" );
document.write( "   h(7) = 7\r\n" );
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document.write( "Then h-1(h(7)) = h-1(7) = \r\n" );
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document.write( "then find h-1 of 7\r\n" );
document.write( "by plugging 7 in for x.\r\n" );
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document.write( "h-1(x) = (x+14)/3\r\n" );
document.write( "h-1(7) = (7+14)/3\r\n" );
document.write( "h-1(7) = 21/3\r\n" );
document.write( "h-1(7) = 7\r\n" );
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document.write( "h-1(h(7)) = h-1(7) = 7.  So when a function is\r\n" );
document.write( "composed with its inverse, you get a function that gives you back the same\r\n" );
document.write( "number for y that you substituted for x.  That's analogous to 7x1=7, like\r\n" );
document.write( "multiplying by 1 or adding 0.  \r\n" );
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document.write( "Edwin
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