document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=855451>Question 855451</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the exact solutions of the equation in the interval [0, 2&#960;)<BR>\n" );
document.write( "(7 sin 2x + 7 cos 2x)^2 = 49 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #515468 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=515468\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hint: I'll get you started\r<BR>\n" );
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document.write( "( 7sin(2x) + 7cos(2x) )^2 = 49\r<BR>\n" );
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document.write( "7sin(2x) + 7cos(2x) = 7 or 7sin(2x) + 7cos(2x) = -7 ... <font color=\"blue\">take the square root of both sides (don't forget about the plus/minus)</font>\r<BR>\n" );
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document.write( "sin(2x) + cos(2x) = 1 or sin(2x) + cos(2x) = -1 ... <font color=\"blue\">divide everything by 7</font> </SPAN>\n" );
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