document.write( "Question 855600: The base of a right triangle is decreasing at a rate of 2 inches per minute, and the height of the triangle is increasing at a rate of 4 inches per minute. When the base of the triangle is 2 feet and the height is 3 feet, how fast is the area of the triangle changing in square inches per minute? \n" ); document.write( "
Algebra.Com's Answer #515457 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
The way I see it, this is a calculus problem.
\n" ); document.write( "With \"t\"= time (in minutes) counted from the moment the base of the triangle is 2 feet and the height is 3 feet,
\n" ); document.write( "the base (in inches), height (in inches), and area (in square inches) are all functions of \"t\" :
\n" ); document.write( "\"base=2%2A12-2t=24-2t\"
\n" ); document.write( "\"height=3%2A12%2B4t=36%2B4t\"
\n" ); document.write( "
\n" ); document.write( "The rate of change of the area (in square inches per minute) is
\n" ); document.write( "\"dArea%2Fdt=12-8t\" which changes with time.
\n" ); document.write( "At \"t=0\" (the moment the base of the triangle is 2 feet and the height is 3 feet)
\n" ); document.write( "\"dArea%2Fdt=12-8%2A1=highlight%2812%29\"
\n" ); document.write( "
\n" ); document.write( "Without invoking calculus, the only solution I see is saying that the rate is the slope of the tangent to the graph.
\n" ); document.write( "With \"x=t\" and \"y=Area-432=12t-4t%5E2=12x-4x%5E2\" the graph would be
\n" ); document.write( "\"graph%28300%2C300%2C-5%2C5%2C-25%2C25%2C12x-4x%5E2%2C12x%29\" .
\n" ); document.write( "The tangent \"y=kx\" , with slope \"k\" passes through the origin
\n" ); document.write( "and intersects \"y=12x-4x%5E2\" at only one point.
\n" ); document.write( "That means that \"kx=12x-4x%5E2\" must have only one solution.
\n" ); document.write( "\"kx=12x-4x%5E2\"<-->\"4x%5E2-12x%2Bkx=0\"<-->\"4x%5E2%2B%28k-12%29x=0\"<-->\"x%284x%2Bk-12%29=0\"
\n" ); document.write( "has the solutions \"x=0\" and \"x=%2812-k%29%2F4\" .
\n" ); document.write( "Those solutions are the same only when \"12-k=0\"<-->\"k=12\" ,
\n" ); document.write( "which makes the line tangent.
\n" ); document.write( "A line with another slope would intersect the graph at two different points, with \"x=0\" , and \"x=%2812-k%29%2F4\" .
\n" ); document.write( "
\n" );