document.write( "Question 855428: let theta be angle in quadrant II such that sec(theta)=-10/7. Find the exact values of cot(theta) and sin(theta) \n" ); document.write( "
Algebra.Com's Answer #515352 by Theo(13342)\"\" \"About 
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T = Theta.
\n" ); document.write( "sec(T) = -10/7
\n" ); document.write( "this means that the hypotenusse is 10 and the adjacent side of the angle is -7.
\n" ); document.write( "you can find the opposite side of the angle by the pythagorean formula.
\n" ); document.write( "c^2 = a^2 + b^2
\n" ); document.write( "c = 10
\n" ); document.write( "a = -7
\n" ); document.write( "from that formula, solve for b^2 to get:
\n" ); document.write( "b^2 = c^2 - a^2
\n" ); document.write( "substitute for c and a in that formula to get:
\n" ); document.write( "b^2 = (10)^2 - (-7)^2 to get:
\n" ); document.write( "b^2 = 100 - 49 which becomes:
\n" ); document.write( "b^2 = 51 which makes:
\n" ); document.write( "b = sqrt(51)\r
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\n" ); document.write( "\n" ); document.write( "you now have:
\n" ); document.write( "angle = T
\n" ); document.write( "hypotenuse = 10
\n" ); document.write( "a = -7
\n" ); document.write( "b = sqrt(51)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "you want to find cot(T):\r
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\n" ); document.write( "\n" ); document.write( "cot(T) = adjacent / opposite = -7/sqrt(51)\r
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\n" ); document.write( "\n" ); document.write( "you want to find sin(T):\r
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\n" ); document.write( "\n" ); document.write( "sin(T) = opposite / hypotenuse = sqrt(51) / 10.\r
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\n" ); document.write( "\n" ); document.write( "you can use your calculator to confirm that you did all this correctly.\r
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\n" ); document.write( "\n" ); document.write( "my method is as follows:\r
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\n" ); document.write( "\n" ); document.write( "assume the angle is in quadrant 1.
\n" ); document.write( "then all of the functions will be positive.
\n" ); document.write( "so solve for the angle as if the angle was in quadrant 1.
\n" ); document.write( "you were given that sec(T) = -10/7
\n" ); document.write( "if T were in quadrant 1, you would get sec(T) = 10/7.
\n" ); document.write( "since sec(T) = 1/cos(T), then solve for:
\n" ); document.write( "1/cos(T) = 10/7
\n" ); document.write( "solving for cos(t) results in:
\n" ); document.write( "cos(T) = 7/10.
\n" ); document.write( "use your calculator to find T to get:
\n" ); document.write( "T = 45.572996
\n" ); document.write( "that's in quadrant 1.
\n" ); document.write( "in quadrant 2, the angle would be (180 - 45.572996) which makes:
\n" ); document.write( "T = 134.427004\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "now that you have the angle in quadrant 2, you can check to see if you got the other values correctly.\r
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\n" ); document.write( "\n" ); document.write( "sec(134.427004) = -1.428571429
\n" ); document.write( "sin(134.427004) = .7141428429
\n" ); document.write( "cot(134.427004) = -.9801960588\r
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\n" ); document.write( "\n" ); document.write( "to confirm that these values are the same as the values you previously calculated, do the following:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "previously you got or were given:
\n" ); document.write( "sec(T) = -10 / 7
\n" ); document.write( "sin(T) = sqrt(51)/10
\n" ); document.write( "cot(T) = -7/sqrt(51)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "put -10/7 in your calculator and you get -1.428571429 which matches sec(134.427004) so that answer is good.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "put sqrt(51)/10 in your calculator and you get .7141428429 which matches sin(134.427004) so that answer is good.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "put -7/sqrt(51) in your calculator and you get -.9801960588 which matches cot(134.427004) so that answer is good.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "everything checks out and your answer is:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "sin(T) = sqrt(51) / 10\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "cot(t) = -7 / sqrt(51)\r
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\n" ); document.write( "\n" ); document.write( "a picture of your angle is attached.\r
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