document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=855207>Question 855207</A>: <I><SPAN STYLE=\"word-break: break-all;\"> draw a square of side 6cm circumscribe a circle about that square and then inscribe a circle in the same square.measure the radii of these two circle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #515322 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=515322\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> draw a square of side 6cm circumscribe a circle about that square and then inscribe a circle in the same square.measure the radii of these two circle.<BR>\n" );
document.write( ":<BR>\n" );
document.write( "The diameter of the inner circle will be 6 cm, the radius will be 3cm<BR>\n" );
document.write( "The diameter of the outer circle will be the hypotenuse of the square<BR>\n" );
document.write( "d = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Sqrt%286%5E2+%2B+6%5E2%29 ALIGN=MIDDLE  ALT=\"Sqrt%286%5E2+%2B+6%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
document.write( "d = 8.48523 <BR>\n" );
document.write( "r = 8.48523/2<BR>\n" );
document.write( "r = 4.24 cm radius of the outer circle </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );