document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=855389>Question 855389</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Substitution method: <BR>\n" );
document.write( "3x-6y=-2<BR>\n" );
document.write( "2x-3y=1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #515315 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39618)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=515315\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Pick an equation and solve for either variable.<BR>\n" );
document.write( "3x-6y=-2<BR>\n" );
document.write( "3x=6y-2<BR>\n" );
document.write( "x=2y-2/3<BR>\n" );
document.write( "Substitute into the other equation.<BR>\n" );
document.write( "2(x)-3y=1<BR>\n" );
document.write( "2(2y-2/3)-3y=1<BR>\n" );
document.write( "4y-4/3-3y=1<BR>\n" );
document.write( "y-4/3=1<BR>\n" );
document.write( "y=4/3+1<BR>\n" );
document.write( "y=7/3 and use this to find the value for x. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );