document.write( "Question 855287: The length of a fence is 4 feet less than twice the width. Find the dimensions if 32 feet of fence is used along three sides of it. \n" ); document.write( "
Algebra.Com's Answer #515299 by JulietG(1812)\"\" \"About 
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L = 2W - 4 [The length of a fence is 4 feet less than twice the width.]
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\n" ); document.write( "Not quite sure what the question is asking -- \"if 32 feet of fence is used along three sides of it.\" Does it mean that 32' is part of the perimeter? We'll assume so.
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\n" ); document.write( "If we know that 32' is 2L+w or 2W+l (because the perimeter is (2L + 2W), we can solve both ways.
\n" ); document.write( "Let's do 2W + L = 32 first.
\n" ); document.write( "Substitute the value of L from the first equation.
\n" ); document.write( "2W + (2W - 4) = 32
\n" ); document.write( "4W - 4 = 32
\n" ); document.write( "Add 4 to each side
\n" ); document.write( "4W = 36
\n" ); document.write( "Divide by 4
\n" ); document.write( "W = 9
\n" ); document.write( "If the width is 9, then L = 2(9)-4, or 18-4, or 14
\n" ); document.write( "W = 9 and L = 14. The perimeter would be (2*9) + (2*14), or 18 + 28 = 46
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\n" ); document.write( "Let's solve it the second way.
\n" ); document.write( "2L + w = 32
\n" ); document.write( "Substitute the value of L from the first equation.
\n" ); document.write( "2(2W - 4) + W = 32
\n" ); document.write( "Distribute
\n" ); document.write( "4W - 8 + W = 32
\n" ); document.write( "5W - 8 = 32
\n" ); document.write( "Add 8 to each side
\n" ); document.write( "5W = 40
\n" ); document.write( "Divide by 5
\n" ); document.write( "W = 8
\n" ); document.write( "If W is 8, then L is (2*8)-4 or 16-4, or 12
\n" ); document.write( "Two lengths for the perimeter = 24 + two widths = 16. 16+24=40 \n" ); document.write( "
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