document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=855356>Question 855356</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Greg is twice as old as Judy. Three years ago, Greg was 3 times as old as Judy was then. Find their current ages. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #515296 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=515296\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> G = 2J [Greg is twice as old as Judy.]<BR>\n" );
document.write( "G - 3 = 3(J -3) [Three years ago, Greg was 3 times as old as Judy was then. ]<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Substitute the value of G in the first equation into the second equation.<BR>\n" );
document.write( "(2J) - 3 = 3(J-3)<BR>\n" );
document.write( "Distribute<BR>\n" );
document.write( "2J - 3 = 3J - 9<BR>\n" );
document.write( "Subtract 2J from each side<BR>\n" );
document.write( "-3 = J - 9<BR>\n" );
document.write( "Add 9 to each side<BR>\n" );
document.write( "6 = J<BR>\n" );
document.write( ".<BR>\n" );
document.write( "If Judy is 6, and Greg is twice her age, then Greg is 12.  <BR>\n" );
document.write( "Let's plug it into the second equation to make sure it's correct.<BR>\n" );
document.write( "G - 3 = 3(J -3)<BR>\n" );
document.write( "12 - 3 = 3(6-3)<BR>\n" );
document.write( "9 = 3(3)<BR>\n" );
document.write( "9 = 9<BR>\n" );
document.write( "Success! </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );