document.write( "Question 855331: the current in the lazy river moves at a rate of 4mph. vlads motors 6 miles upstream in the same time it takes 12 mi downstream. what is the speed in still water? \n" ); document.write( "
Algebra.Com's Answer #515260 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( "what is the speed \"+highlight_green%28x%29\"in still water?
\n" ); document.write( "\"6mi%2F%28x-4mph%29+=+12mi%2F%28x%2B4mph%29\"
\n" ); document.write( " 12x - 48 = 6x + 24
\n" ); document.write( " 6x = 72
\n" ); document.write( " x = 12mph
\n" ); document.write( "CHECKING our answer***
\n" ); document.write( "\"6%2F8+=+12%2F16+=+3%2F4\" Note 3/4 hr is the time it took going up and back, as well.
\n" ); document.write( "Wish You the Best in your Studies.
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