document.write( "Question 855313: how do you do the problem x^4-12x^2+11=0 when trying to factor the expression on the left side of each equation \n" ); document.write( "
Algebra.Com's Answer #515239 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
The polynomial is in quadratic form. You can replace like, \"u=x%5E2\". The constant terms in each binomial factor will need to give product of 11 and sum of -12. The obvious and correct choice will be -1 and -11.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%5E2-1%29%28x%5E2-11%29=0\"
\n" ); document.write( "-
\n" ); document.write( "The solutions will be Real Numbers:
\n" ); document.write( "EITHER \"x%5E2-1=0\"
\n" ); document.write( "\"x%5E2=1\"
\n" ); document.write( "\"x=1\" or \"x=-1\"
\n" ); document.write( "OR
\n" ); document.write( "\"x%5E2-11=0\"
\n" ); document.write( "\"x%5E2=11\"
\n" ); document.write( "\"x=sqrt%2811%29\" or \"x=-sqrt%2811%29\"\r
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\n" ); document.write( "\n" ); document.write( "SUMMARY: possible solutions for x are -1, 1, -sqrt(11), sqrt(11)
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