document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=855226>Question 855226</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sizes of computer monitors and television screens are found by measuring the length of the diagonal of the rectangular screen. the 50 inch rectangular tv below has a bottom length of 41 inches. what is the height of the screen? Moderate complexity </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #515169 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=515169\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  the sizes of computer monitors and television screens are found by measuring the length of the diagonal of the rectangular screen. the 50 inch rectangular tv below has a bottom length of 41 inches. what is the height of the screen? <BR>\n" );
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document.write( "diag^2 = length^2 + height^2<BR>\n" );
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document.write( "50^2 = 41^2 + height^2<BR>\n" );
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document.write( "height = sqrt[50^2-41^2] = 28.61<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "==================== </SPAN>\n" );
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