document.write( "Question 855105: how do you solve\r
\n" ); document.write( "\n" ); document.write( "log(x+2)-log(x-1)=logx-log(x=3)
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Algebra.Com's Answer #515133 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
this is problem number 855105.\r
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\n" ); document.write( "\n" ); document.write( "the properties of logs that you will use are:\r
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\n" ); document.write( "\n" ); document.write( "log(a) - log(b) = log(a/b)
\n" ); document.write( "if log(a) = log(b), then a = b.\r
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\n" ); document.write( "\n" ); document.write( "before i can solve this for you, i need you to check your original equation to make sure you entered it correctly.\r
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\n" ); document.write( "\n" ); document.write( "you show (x=3)\r
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\n" ); document.write( "\n" ); document.write( "did you mean (x+3) or did you mean (x-3) or did you mean something else?\r
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\n" ); document.write( "\n" ); document.write( "i did some preliminary analysis and i don't see a solution to this problem, so it's important to make sure you have shown the problem correctly.\r
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\n" ); document.write( "\n" ); document.write( "check it again and get back to me with a revised original equation.\r
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\n" ); document.write( "\n" ); document.write( "i'll then look at it again and get back to you.\r
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\n" ); document.write( "\n" ); document.write( "your original question is:\r
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\n" ); document.write( "\n" ); document.write( "how do you solve
\n" ); document.write( "log(x+2)-log(x-1)=logx-log(x=3)\r
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