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The length of a rectangle is 7 feet longer than it is wide. If each side is increased 7 feet, then the area is multiplied by 4. What was the size of the original rectangle?
\n" ); document.write( "Answer
\n" ); document.write( "Let width of rectangle is x feet
\n" ); document.write( "length will be x+7 feet\r
\n" ); document.write( "\n" ); document.write( "area of rectangle =lenghxwidth
\n" ); document.write( " area of rectangle =x(x+7)
\n" ); document.write( "now as per given conditions if 7 feet is increased area willbe 4 times
\n" ); document.write( "new width =x+7
\n" ); document.write( "length =x+7+7=x+14
\n" ); document.write( "new area will be =(x+7)(x+14)
\n" ); document.write( "as per given conditions
\n" ); document.write( "(x+7)(x+14)=4x(x+7)
\n" ); document.write( "x^2+21x+98=4x^2+28x
\n" ); document.write( "0=4x^2+28x-x^2-21x-98
\n" ); document.write( "3X^2+7x-98=0
\n" ); document.write( "3x^2-14x+21x-98=0
\n" ); document.write( "x(3x-14)+7(3x-14)=0
\n" ); document.write( "x+7=0 or 3x-14=0
\n" ); document.write( "x=-7 0r x=14/3 feet
\n" ); document.write( "neglecting negative 7 as diamension can not be negative
\n" ); document.write( "width =14/3 feet
\n" ); document.write( "and length=14/3+7=35/3 feet
\n" ); document.write( "Answer
\n" ); document.write( "length will be =35/3 feet
\n" ); document.write( "width will be =14/3 feet
\n" ); document.write( "verification
\n" ); document.write( "area=14/3x35/3
\n" ); document.write( "new area will be
\n" ); document.write( " =56/3x35/3=4(14/3x35/3) verified as per condition area 4 times of old area \n" ); document.write( "