document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=855083>Question 855083</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The equation of a line perpendicular to the given line but passing through the given point y=-2/3x+2 (9,-3). My answer is y = (3/2)x - (33/2)but I don't know how to graph this because its to big, can it be reduced? My graph only goes to -4<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #515079 by </B><A HREF=/tutors/aboutme.mpl?userid=KMST><B>KMST(5328)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=KMST><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=KMST><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=515079\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Your line does not make a nice graph.<BR>\n" );
document.write( "I like to include the origin, and pieces of the x-axis and y-axis to both sides.<BR>\n" );
document.write( "In this case, including the y-intercept (0,-33/2) would be difficult.<BR>\n" );
document.write( "Even including point (9,-3) may be tricky.<BR>\n" );
document.write( "You only need two points (or one point and the slope) to draw a line, and you could use any point(s) for your line.<BR>\n" );
document.write( "in line <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=%283%2F2%29x-33%2F2 ALIGN=MIDDLE  ALT=\"y=%283%2F2%29x-33%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" > , for <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=9 ALIGN=MIDDLE  ALT=\"x=9\"   DISABLED_style= \"max-width:90%; height:auto;\" > --> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=-3 ALIGN=MIDDLE  ALT=\"y=-3\"   DISABLED_style= \"max-width:90%; height:auto;\" > (point (9,-3) as required),<BR>\n" );
document.write( "and a slope of <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%2F2 ALIGN=MIDDLE  ALT=\"3%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" > means that<BR>\n" );
document.write( "as <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x ALIGN=MIDDLE  ALT=\"x\"   DISABLED_style= \"max-width:90%; height:auto;\" > increases by <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2 ALIGN=MIDDLE  ALT=\"2\"   DISABLED_style= \"max-width:90%; height:auto;\" > , <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y ALIGN=MIDDLE  ALT=\"y\"   DISABLED_style= \"max-width:90%; height:auto;\" > increases by <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3 ALIGN=MIDDLE  ALT=\"3\"   DISABLED_style= \"max-width:90%; height:auto;\" > .<BR>\n" );
document.write( "That gives us points (11,0), (13,3), (15,6).<BR>\n" );
document.write( "For line <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=%28-2%2F3%29x%2B2 ALIGN=MIDDLE  ALT=\"y=%28-2%2F3%29x%2B2\"   DISABLED_style= \"max-width:90%; height:auto;\" > we could use point (0,2), and a slope of <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-2%2F3 ALIGN=MIDDLE  ALT=\"-2%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" > would take us to (3,0), (6,-2), and (9,-5)<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=drawing%28300%2C300%2C-2%2C18%2C-6%2C14%2C%0D%0Agrid%281%29%2Cblue%28line%28-3%2C4%2C12%2C-6%29%29%2C%0D%0Ablue%28circle%280%2C2%2C0.3%29%29%2Cblue%28circle%286%2C-2%2C0.3%29%29%2C%0D%0Agreen%28line%285%2C-9%2C19%2C12%29%29%2C%0D%0Agreen%28circle%289%2C-3%2C0.4%29%29%2Cgreen%28circle%2811%2C0%2C0.4%29%29%2C%0D%0Agreen%28circle%2813%2C3%2C0.4%29%29%0D%0A%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );