document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=72018>Question 72018</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the following system of equations using the substitution method: <BR>\n" );
document.write( "4x - y = -6 <BR>\n" );
document.write( "x + 2y = 3 \r<BR>\n" );
document.write( "\n" );
document.write( "please show work </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #51506 by </B><A HREF=/tutors/aboutme.mpl?userid=elima><B>elima(1433)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=elima><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=51506\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4x - y = -6 <BR>\n" );
document.write( "x + 2y = 3 <BR>\n" );
document.write( "First solve one of the equations for either x or y, we will go ahead and solve the second one for x;<BR>\n" );
document.write( "x +2y =3<BR>\n" );
document.write( "x = 3-2y<BR>\n" );
document.write( "now substitute the this equation for x in the first equation;<BR>\n" );
document.write( "4(3-2y)-y=-6<BR>\n" );
document.write( "12-8y-y=-6<BR>\n" );
document.write( "12-9y=-6<BR>\n" );
document.write( "-9y = -6-12<BR>\n" );
document.write( "-9y = -18<BR>\n" );
document.write( "y = 2<BR>\n" );
document.write( "Now that we have what y equals lets plug that in for y in the second equation;<BR>\n" );
document.write( "x + 2(2) = 3<BR>\n" );
document.write( "x + 4 = 3<BR>\n" );
document.write( "x = 3-4<BR>\n" );
document.write( "x = -1<BR>\n" );
document.write( "So we have;<BR>\n" );
document.write( "(-1,2)<BR>\n" );
document.write( ":) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );