document.write( "Question 855096: how do i solve\r
\n" ); document.write( "\n" ); document.write( "2logx+log4=2 \n" ); document.write( "

Algebra.Com's Answer #515059 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
The trick is to express $\"+2+\"$ as a log
\n" ); document.write( " $\"+2+=+log%28+100+%29+\"$
\n" ); document.write( " $\"+2%2Alog%28+x+%29+%2B+log%28+4+%29+=+2+\"$
\n" ); document.write( " $\"+2%2Alog%28+x+%29+%2B+log%28+4+%29+=+log%28+100+%29+\"$
\n" ); document.write( " $\"+log%28+x%5E2+%29+%2B+log%284%29+=+log%28+100+%29+\"$
\n" ); document.write( " $\"+log%28+4x%5E2+%29+=+log%28+100+%29+\"$
\n" ); document.write( " $\"+4x%5E2+=+100+\"$
\n" ); document.write( " $\"+x%5E2+=+25+\"$
\n" ); document.write( " $\"+x+=+5+\"$
\n" ); document.write( "-------------
\n" ); document.write( "check:
\n" ); document.write( " $\"+2%2Alog%28+x+%29+%2B+log%28+4+%29+=+2+\"$
\n" ); document.write( " $\"+2%2Alog%28+5+%29+%2B+log%28+4+%29+=+2+\"$
\n" ); document.write( " $\"+2%2A.69897+%2B+.60206+=+2+\"$
\n" ); document.write( " $\"+1.39794+%2B+.60206+=+2+\"$
\n" ); document.write( " $\"+2+=+2+\"$
\n" ); document.write( "Ok
\n" ); document.write( "---------
\n" ); document.write( "Also note that $\"+x+=+-5+\"$ the other square root
\n" ); document.write( "doesn't work because $\"+log%28%28+-5+%29%29+\"$ makes no sense.
\n" ); document.write( "You can't raise base 10 to an exponent and
\n" ); document.write( "get a negative result.
\n" ); document.write( " \n" ); document.write( "

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