document.write( "Question 854988: I keep confusing myself I do not understand the slope formula and I have an assignment due today. The equation of a line perpendicular to the given line but passing through the given point y=-2/3x+2 (9,-3) \n" ); document.write( "

Algebra.Com's Answer #515006 by richwmiller(17219) $\"\"$ $\"About$

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y=mx+b
\n" ); document.write( "m is the slope and
\n" ); document.write( "b is the value of y when x=0 It is often called the y intercept
\n" ); document.write( "Parallel lines have the same slope
\n" ); document.write( "the product of the slopes of perpendicular lines is -1
\n" ); document.write( "so if the slope of one line is 4 the slope of the other is -1/4 (4*-1/4=-1)
\n" ); document.write( "The slope of the line y=-2/3x+2 is -2/3
\n" ); document.write( "So the slope of the line perpendicular line is 3/2 \r
\n" ); document.write( "\n" ); document.write( "3/2*(-2/3)=-1\r
\n" ); document.write( "\n" ); document.write( "point (9,-3)
\n" ); document.write( "y=mx+b
\n" ); document.write( " m = 3/2, x = 9, y = -3
\n" ); document.write( "-3=3/2*(9)+b
\n" ); document.write( "b = -33/2,\r
\n" ); document.write( "\n" ); document.write( "y=3x/2-33/2\r
\n" ); document.write( "\n" ); document.write( "the two perpendicular lines cross at x = 111/13, y = -48/13 \n" ); document.write( "

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