document.write( "Question 854903: \r
\n" ); document.write( "\n" ); document.write( "If an investment is $9500, part of it at 11% and part of it at 8%. For a certain year the total is $937. How much was invested at each rate?
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Algebra.Com's Answer #514989 by checkley79(3341)\"\" \"About 
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.11x+.08(9500-x)=937
\n" ); document.write( ".11x+760-.08x=937
\n" ); document.write( ".03x=937-760
\n" ); document.write( ".03x=177
\n" ); document.write( "x=177/.03
\n" ); document.write( "x=$5,900 invested @ 11%
\n" ); document.write( "9,500-5,900=$3,600 invested @ 8%
\n" ); document.write( "Proof:
\n" ); document.write( ".11*5,900+.08*3,600=937
\n" ); document.write( "649+288=937
\n" ); document.write( "937=937
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