document.write( "Question 854923: Solve log2 (y+1) + log2 (3y-1) = 5 \n" ); document.write( "

Algebra.Com's Answer #514986 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

 
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document.write( "Hi,
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document.write( "log2 (y+1) + log2 (3y-1) = 5 
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document.write( "     (y+1)(3y-1)) = 2^5
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document.write( "     3y^2 + 2y - 1 = 32
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document.write( "     3y^2 + 2y - 33 = 0
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document.write( "x =  (Tossing out this negative root as Extraneous)
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document.write( "x =
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