document.write( "Question 854849: We throw 2 dice and we suppose that 6 x 6 = 36 outcomes have equal probability. Let B the event that we get two \"6\". Count P(B|A) for the following occasions for the event A:\r
\n" ); document.write( "\n" ); document.write( "i) A is the event that we get two \"6\", which means A = B.
\n" ); document.write( "ii) A is the event that both dices can have even outcome.
\n" ); document.write( "iii) A is the event that we get double, which means that we get same outcome on both dices.
\n" ); document.write( "iv) A is the event that we can get any outcome, which means A = S.
\n" ); document.write( "v) A is the event that both dices can have odd outcome. \n" ); document.write( "

Algebra.Com's Answer #514954 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

 
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document.write( "Hi,
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document.write( "Using counting: each of the 36 outcomes have equal probability of 1/36
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document.write( "i) P(two 6s) = 1/36 
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document.write( "ii)P(both even)=   
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document.write( "0r   (half on each dice are even numbers)
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document.write( "iii)P(double) = 6/36 = 1/6 
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document.write( "iv) P(any outcome) = 36/36
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document.write( "v)  P(both odd)) = 9/36 = 1/4 
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document.write( "List both even outcomes to check
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document.write( "2,2
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document.write( "2,4
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document.write( "4,2
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document.write( "2,6
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document.write( "6,2
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document.write( "4,4
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document.write( "4,6
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document.write( "6,4
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document.write( "6,6
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document.write( " \n" );
document.write( "

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