document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=854635>Question 854635</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Landon can climb a certain hill at a rate this is 0.5 mph slower than his rate coming down the hill. If it takes him 4 hours to climb the hill and 216 minutes to come down the hill, what is his rate coming down? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #514919 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=514919\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4 hours=240 minutes climb<BR>\n" );
document.write( "3.6= 216 minutes descend<BR>\n" );
document.write( "x*3.6=4*(x-.5)<BR>\n" );
document.write( "x = 5. mph downhill<BR>\n" );
document.write( "x-.5=4.5 mph uphill= 18 miles<BR>\n" );
document.write( "5*3.6=18 miles\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );