document.write( "Question 854651: The probability of a randomly selected car crashing during the year is .0423. If a family has three cars, find the probability that at least one of them has a crash during the year? Thank you for the help. \n" ); document.write( "
Algebra.Com's Answer #514887 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( " p(crash)= .0423, p(no crash) = .9577
\n" ); document.write( "3 cars
\n" ); document.write( "P(at least one crash) = 1 - P(no crash) = 1 - (.9577)^3 = 1- .8784 = .1216
\n" ); document.write( "Using \"P+%28x%29=+highlight_green%28nCx%29%28p%5Ex%29%28q%29%5E%28n-x%29+\"
\n" ); document.write( "P(no crash) = (.9577)^3 \n" ); document.write( "
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