document.write( "Question 854744: A plane leaves an airport and flies at 360mi/hr on a course of 103° 15' for 1hr and 33minutes. Then it changes course to 236°45' and flies for 48minutes. How far is it from the airport? If it wished to return, what would be its course? \n" ); document.write( "
Algebra.Com's Answer #514873 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! A plane leaves an airport and flies at 360mi/hr on a course of 103° 15' for 1hr and 33minutes. Then it changes course to 236°45' and flies for 48minutes. How far is it from the airport? If it wished to return, what would be its course? \n" ); document.write( "-------------------- \n" ); document.write( "360 mi/hr = 6 mi/minute \n" ); document.write( "103° 15' = 103.25° \n" ); document.write( "236° 45' = 236.75° \n" ); document.write( "---- \n" ); document.write( "Label the start point A, then B & C \n" ); document.write( "AB = 6*93 = 558 miles (side c) \n" ); document.write( "BC = 6*48 = 288 miles (side a) \n" ); document.write( "Angle at B = 46.5 degs \n" ); document.write( "----- \n" ); document.write( "Side b = distance from start \n" ); document.write( " \n" ); document.write( "------- \n" ); document.write( "Ude Law of Sines to find the heading back to A \n" ); document.write( " \n" ); document.write( " |