document.write( "Question 854744: A plane leaves an airport and flies at 360mi/hr on a course of 103° 15' for 1hr and 33minutes. Then it changes course to 236°45' and flies for 48minutes. How far is it from the airport? If it wished to return, what would be its course? \n" ); document.write( "
Algebra.Com's Answer #514873 by Alan3354(69443)\"\" \"About 
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A plane leaves an airport and flies at 360mi/hr on a course of 103° 15' for 1hr and 33minutes. Then it changes course to 236°45' and flies for 48minutes. How far is it from the airport? If it wished to return, what would be its course?
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\n" ); document.write( "360 mi/hr = 6 mi/minute
\n" ); document.write( "103° 15' = 103.25°
\n" ); document.write( "236° 45' = 236.75°
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\n" ); document.write( "Label the start point A, then B & C
\n" ); document.write( "AB = 6*93 = 558 miles (side c)
\n" ); document.write( "BC = 6*48 = 288 miles (side a)
\n" ); document.write( "Angle at B = 46.5 degs
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\n" ); document.write( "Side b = distance from start
\n" ); document.write( "\"b%5E2+=+a%5E2+%2B+c%5E2+-+2ac%2Acos%28B%29\"
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\n" ); document.write( "Ude Law of Sines to find the heading back to A
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