document.write( "Question 854698: A household with three children is selected randomly. The children are reported according to their gender and serial number of their birth. What is the probability that the household has 2 boys. Show the calculation. \n" ); document.write( "
Algebra.Com's Answer #514872 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
\n" ); document.write( "Hi,
\n" ); document.write( "three children: p(boy) = 1/2, p(girl) = 1/2
\n" ); document.write( "May use Binomial Distribution Formula:\"P+%28x%29=+highlight_green%28nCx%29%28p%5Ex%29%28q%29%5E%28n-x%29+\"
\n" ); document.write( "P(x = 2 boys) = \"3%281%2F2%29%5E2%281%2F2%29%5E1+=+3%2F8\" |Note 3C2 = 3
\n" ); document.write( "Or counting
\n" ); document.write( "Note: 3 possible outcomes for the order 2 boys were born, P = 1/8 for each of them
\n" ); document.write( "GBB
\n" ); document.write( "BGB
\n" ); document.write( "BBG
\n" ); document.write( "P(x = 2 boys) = \"3%281%2F8%29+=+3%2F8\"
\n" ); document.write( " \n" ); document.write( "
\n" );