document.write( "Question 854708: Sec squared 45 - csc squared 30 \n" ); document.write( "
Algebra.Com's Answer #514864 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Sec squared 45 - csc squared 30 \n" ); document.write( "------- \n" ); document.write( "sec^2(45) - csc^2(30) = (2/sqrt(2))^2 - 2^2 = 4/2-4 = -2 \n" ); document.write( "================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================== \n" ); document.write( " |