document.write( "Question 854708: Sec squared 45 - csc squared 30 \n" ); document.write( "
Algebra.Com's Answer #514864 by stanbon(75887)\"\" \"About 
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Sec squared 45 - csc squared 30
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\n" ); document.write( "sec^2(45) - csc^2(30) = (2/sqrt(2))^2 - 2^2 = 4/2-4 = -2
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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