document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=854741>Question 854741</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello. Lately, I've been really confused about applying the unit circle to trigonometric functions and I still don't understand how 25pi/6 would equal 1/2 using the unit circle... However, I do understand that one full rotation around the unit circle is equivalent to 2pi or 6pi/3 if I'm not mistaken. If you could help me that would be greatly appreciated. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #514863 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=514863\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I still don't understand how 25pi/6 would equal 1/2 using the unit circle.<BR>\n" );
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document.write( "(25/6)pi = (4 + 1/6)pi<BR>\n" );
document.write( "4pi is just twice around the circle.<BR>\n" );
document.write( "So, (4+ 1/6)pi = (1/6)pi<BR>\n" );
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document.write( "Not sure what you mean when you say 25pi/6 = 1/2<BR>\n" );
document.write( "It doesn't.<BR>\n" );
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document.write( "Maybe you meant sin(25pi/6) = sin(pi/6) = 1/2<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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