document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=854714>Question 854714</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If A and B are dependent events, which of these conditions must be true?\r<BR>\n" );
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document.write( "P(A and B)=P(A) + P(B)\r<BR>\n" );
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document.write( "P(A and B)=  P(B)<BR>\n" );
document.write( "          P(A)\r<BR>\n" );
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document.write( "P(B|A)=P(B)\r<BR>\n" );
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document.write( "P(A|B)=P(A)\r<BR>\n" );
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document.write( "P(B|A) does not equal P(B)\r<BR>\n" );
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document.write( "I think its the first one. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #514853 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=514853\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Not quite. For example, suppose A and B only occur together, that is, B is true if and only if A is true, and suppose P(A) = 1/2. Then P(B) = 1/2, so P(A and B) = 1/2 but P(A) + P(B) = 1.\r<BR>\n" );
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document.write( "The last condition must be true -- if P(B|A) = P(B), then A and B are independent. </SPAN>\n" );
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