document.write( "Question 854669: suppose that all possible card selections are equally likely, what probability should be assigned to each selection?
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document.write( "Find the probability that you choose a face card.(j,q,k,a)
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document.write( "Find the probability that you choose a black card, spade or club.
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document.write( "consider the events\" draw a face card and draw a 5 or smaller'. Are these events overlapping or disjoint? explain
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document.write( "Find the probability of drawing a red card or a spade. \n" );
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Algebra.Com's Answer #514816 by Theo(13342)![]() ![]() You can put this solution on YOUR website! 52 cards in the deck.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "face card is any card with a face on it. \n" ); document.write( "that would be jack, queen, king. \n" ); document.write( "ace is not considered a face card. \n" ); document.write( "there are 4 jacks, 4 queens, 4 kings in the deck for a total of 12. \n" ); document.write( "probability of getting a face card is 12 / 52 which is equivalent to 3 / 13.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "there are 26 black cards in the deck (spades and clubs) and 26 red cards in the deck (hearts and diamonds). \n" ); document.write( "the probability of getting a black card only is therefore equal to 26/52 = 1/2. \n" ); document.write( "since a spade or a club are both black cards, the probability remains the same. \n" ); document.write( "this is the probability of A or B or C. \n" ); document.write( "A is the probability of getting a black card. \n" ); document.write( "B is the probability of getting a spade. \n" ); document.write( "C is the probability of getting a club.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the formula for the probability of (A or B or C) is equal to the p(A) + p(B) + p(C) - p(AB) - p(AC) - p(BC) + p(ABC).\r \n" ); document.write( "\n" ); document.write( "p(A) = 26/52 \n" ); document.write( "p(B) = 13/52 \n" ); document.write( "p(C) = 13/52 \n" ); document.write( "p(AB) = 13/52 \n" ); document.write( "p(AC) = 13/52 \n" ); document.write( "p(BC) = 0 \n" ); document.write( "p(ABC) = 0\r \n" ); document.write( "\n" ); document.write( "put those numbers in the formula and you get 26/52 as the answer. \n" ); document.write( "p(AB) is 13/52 because there are 13 spades in the deck and they are all black. \n" ); document.write( "p(AC) is 13/52 because there are 13 clubs in the deck and they are all black. \n" ); document.write( "p(BC) is 0 because the same card can't be a spade and a club at the same time. \n" ); document.write( "p(ABC) = 0 because the saem card can't be a spade and a club and a black card at the same time.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the event of drawing a face card and drawing a 5 or smaller are disjoint event. \n" ); document.write( "this is because you can't draw a face card and a 5 or smaller at the same time. \n" ); document.write( "this is because none of the number cards are face cards and so there is no overlap.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "an example of an overlap would be drawing a spade and drawing a 5 or smaller. in this case, there are overlapping events because a 5 or smaller could also be a spade.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the probability of drawing a red card or a spade is equal to 26/52 + 13/52. \n" ); document.write( "this is because red cards and spades are disjoint event. they have nothing in common.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |