document.write( "Question 854673: What are the dimensions of the fenced in area if he only has 190 yards and the length is 10 yards more than 5 times the width? \n" ); document.write( "

Algebra.Com's Answer #514811 by josgarithmetic(39617) $\"\"$ $\"About$

You can put this solution on YOUR website!
x for length, y for width.
\n" ); document.write( "x=10+5y
\n" ); document.write( "Fencing for perimeter is 190 yards.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " $\"2x%2B2y=190\"$
\n" ); document.write( " $\"2%2810%2B5y%29%2B2y=190\"$
\n" ); document.write( " $\"10%2B5y%2By=95\"$
\n" ); document.write( " $\"6y=85\"$
\n" ); document.write( " $\"y=85%2F6=14%261%2F6\"$ ----width
\n" ); document.write( "-
\n" ); document.write( " $\"x=10%2B5%2885%2F6%29\"$
\n" ); document.write( " $\"60%2F6%2B5%2A85%2F6\"$
\n" ); document.write( " $\"485%2F6\"$
\n" ); document.write( " $\"x=80%265%2F6\"$ ----length\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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