document.write( "Question 854666: A runs at 07:00 a.m. With a speed of 10 km/hr.After 2 hrs,B runs with a speed of 20 km/hr, then find when they will meet together. \n" ); document.write( "
Algebra.Com's Answer #514809 by josmiceli(19441)\"\" \"About 
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How far does A get in 2 hrs?
\n" ); document.write( "\"+d%5B1%5D+=+10%2A2+\"
\n" ); document.write( "\"+d%5B1%5D+=+20+\" km
\n" ); document.write( "-----------------------
\n" ); document.write( "Start a stopwatch when B leaves
\n" ); document.write( "Let \"+t+\" = time in hrs when they meet
\n" ); document.write( "Let \"+d+\" = the distance in km that B runs
\n" ); document.write( "-------------------------------------------------
\n" ); document.write( "A's equation:
\n" ); document.write( "(1) \"+d+-+20+=+10t+\"
\n" ); document.write( "B's equation:
\n" ); document.write( "(2) \"+d+=+20t+\"
\n" ); document.write( "-------------------
\n" ); document.write( "Substitute (2) into (1)
\n" ); document.write( "(1) \"+20t+-+20+=+10t+\"
\n" ); document.write( "(1) \"+10t+=+20+\"
\n" ); document.write( "(1) \"+t+=+2+\"
\n" ); document.write( "They will meet 2 hrs after B leaves,
\n" ); document.write( "which is 7:00 + 2 hrs + 2 hrs = 11:00 AM
\n" ); document.write( "check:
\n" ); document.write( "(1) \"+d+-+20+=+10t+\"
\n" ); document.write( "(1) \"+d+-+20+=+10%2A2+\"
\n" ); document.write( "(1) \"+d+=+40+\"
\n" ); document.write( "and
\n" ); document.write( "(2) \"+d+=+20t+\"
\n" ); document.write( "(2) \"+d+=+20%2A2+\"
\n" ); document.write( "(2) \"+d+=+40+\"
\n" ); document.write( "OK
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