document.write( "Question 854666: A runs at 07:00 a.m. With a speed of 10 km/hr.After 2 hrs,B runs with a speed of 20 km/hr, then find when they will meet together. \n" ); document.write( "
Algebra.Com's Answer #514809 by josmiceli(19441) You can put this solution on YOUR website! How far does A get in 2 hrs? \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "----------------------- \n" ); document.write( "Start a stopwatch when B leaves \n" ); document.write( "Let \n" ); document.write( "Let \n" ); document.write( "------------------------------------------------- \n" ); document.write( "A's equation: \n" ); document.write( "(1) \n" ); document.write( "B's equation: \n" ); document.write( "(2) \n" ); document.write( "------------------- \n" ); document.write( "Substitute (2) into (1) \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "They will meet 2 hrs after B leaves, \n" ); document.write( "which is 7:00 + 2 hrs + 2 hrs = 11:00 AM \n" ); document.write( "check: \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "and \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "OK \n" ); document.write( " \n" ); document.write( " |