document.write( "Question 854644: Find the vertex, focus, and directrix of the parabola. Graph the equation.
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document.write( "y^2 - 2y = 8x - 1 \n" );
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Algebra.Com's Answer #514802 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Find the vertex, focus, and directrix of the parabola. Graph the equation. \n" ); document.write( "y^2 - 2y = 8x - 1 \n" ); document.write( "complete the square: \n" ); document.write( "(y^2-2y+1) = 8x - 1+1 \n" ); document.write( "(y-1)^2=8x \n" ); document.write( "This is an equation of a parabola that opens right. \n" ); document.write( "Its basic form of equation: (y-k)^2=4p(x-h)^2, (h,k)=coordinates of the vertex \n" ); document.write( "For given parabola: \n" ); document.write( "vertex: (0,1) \n" ); document.write( "axis of symmetry: y=1 \n" ); document.write( "4p=8 \n" ); document.write( "p=2 \n" ); document.write( "focus: (2,1) (p-distance to the right of vertex on the axis of symmetry) \n" ); document.write( "directrix: x=-2 (p-distance to the left of vertex on the axis of symmetry)\r \n" ); document.write( "\n" ); document.write( "see graph below: \n" ); document.write( "y=(8x)^.5+1 \n" ); document.write( " |